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python36
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lib64
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python3.6
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idlelib
pyparse.py
"""Define partial Python code Parser used by editor and hyperparser. Instances of ParseMap are used with str.translate. The following bound search and match functions are defined: _synchre - start of popular statement; _junkre - whitespace or comment line; _match_stringre: string, possibly without closer; _itemre - line that may have bracket structure start; _closere - line that must be followed by dedent. _chew_ordinaryre - non-special characters. """ import re # Reason last statement is continued (or C_NONE if it's not). (C_NONE, C_BACKSLASH, C_STRING_FIRST_LINE, C_STRING_NEXT_LINES, C_BRACKET) = range(5) # Find what looks like the start of a popular statement. _synchre = re.compile(r""" ^ [ \t]* (?: while | else | def | return | assert | break | class | continue | elif | try | except | raise | import | yield ) \b """, re.VERBOSE | re.MULTILINE).search # Match blank line or non-indenting comment line. _junkre = re.compile(r""" [ \t]* (?: \# \S .* )? \n """, re.VERBOSE).match # Match any flavor of string; the terminating quote is optional # so that we're robust in the face of incomplete program text. _match_stringre = re.compile(r""" \""" [^"\\]* (?: (?: \\. | "(?!"") ) [^"\\]* )* (?: \""" )? | " [^"\\\n]* (?: \\. [^"\\\n]* )* "? | ''' [^'\\]* (?: (?: \\. | '(?!'') ) [^'\\]* )* (?: ''' )? | ' [^'\\\n]* (?: \\. [^'\\\n]* )* '? """, re.VERBOSE | re.DOTALL).match # Match a line that starts with something interesting; # used to find the first item of a bracket structure. _itemre = re.compile(r""" [ \t]* [^\s#\\] # if we match, m.end()-1 is the interesting char """, re.VERBOSE).match # Match start of statements that should be followed by a dedent. _closere = re.compile(r""" \s* (?: return | break | continue | raise | pass ) \b """, re.VERBOSE).match # Chew up non-special chars as quickly as possible. If match is # successful, m.end() less 1 is the index of the last boring char # matched. If match is unsuccessful, the string starts with an # interesting char. _chew_ordinaryre = re.compile(r""" [^[\](){}#'"\\]+ """, re.VERBOSE).match class ParseMap(dict): r"""Dict subclass that maps anything not in dict to 'x'. This is designed to be used with str.translate in study1. Anything not specifically mapped otherwise becomes 'x'. Example: replace everything except whitespace with 'x'. >>> keepwhite = ParseMap((ord(c), ord(c)) for c in ' \t\n\r') >>> "a + b\tc\nd".translate(keepwhite) 'x x x\tx\nx' """ # Calling this triples access time; see bpo-32940 def __missing__(self, key): return 120 # ord('x') # Map all ascii to 120 to avoid __missing__ call, then replace some. trans = ParseMap.fromkeys(range(128), 120) trans.update((ord(c), ord('(')) for c in "({[") # open brackets => '('; trans.update((ord(c), ord(')')) for c in ")}]") # close brackets => ')'. trans.update((ord(c), ord(c)) for c in "\"'\\\n#") # Keep these. class Parser: def __init__(self, indentwidth, tabwidth): self.indentwidth = indentwidth self.tabwidth = tabwidth def set_code(self, s): assert len(s) == 0 or s[-1] == '\n' self.code = s self.study_level = 0 def find_good_parse_start(self, is_char_in_string=None, _synchre=_synchre): """ Return index of a good place to begin parsing, as close to the end of the string as possible. This will be the start of some popular stmt like "if" or "def". Return None if none found: the caller should pass more prior context then, if possible, or if not (the entire program text up until the point of interest has already been tried) pass 0 to set_lo(). This will be reliable iff given a reliable is_char_in_string() function, meaning that when it says "no", it's absolutely guaranteed that the char is not in a string. """ code, pos = self.code, None if not is_char_in_string: # no clue -- make the caller pass everything return None # Peek back from the end for a good place to start, # but don't try too often; pos will be left None, or # bumped to a legitimate synch point. limit = len(code) for tries in range(5): i = code.rfind(":\n", 0, limit) if i < 0: break i = code.rfind('\n', 0, i) + 1 # start of colon line (-1+1=0) m = _synchre(code, i, limit) if m and not is_char_in_string(m.start()): pos = m.start() break limit = i if pos is None: # Nothing looks like a block-opener, or stuff does # but is_char_in_string keeps returning true; most likely # we're in or near a giant string, the colorizer hasn't # caught up enough to be helpful, or there simply *aren't* # any interesting stmts. In any of these cases we're # going to have to parse the whole thing to be sure, so # give it one last try from the start, but stop wasting # time here regardless of the outcome. m = _synchre(code) if m and not is_char_in_string(m.start()): pos = m.start() return pos # Peeking back worked; look forward until _synchre no longer # matches. i = pos + 1 while 1: m = _synchre(code, i) if m: s, i = m.span() if not is_char_in_string(s): pos = s else: break return pos def set_lo(self, lo): """ Throw away the start of the string. Intended to be called with the result of find_good_parse_start(). """ assert lo == 0 or self.code[lo-1] == '\n' if lo > 0: self.code = self.code[lo:] def _study1(self): """Find the line numbers of non-continuation lines. As quickly as humanly possible <wink>, find the line numbers (0- based) of the non-continuation lines. Creates self.{goodlines, continuation}. """ if self.study_level >= 1: return self.study_level = 1 # Map all uninteresting characters to "x", all open brackets # to "(", all close brackets to ")", then collapse runs of # uninteresting characters. This can cut the number of chars # by a factor of 10-40, and so greatly speed the following loop. code = self.code code = code.translate(trans) code = code.replace('xxxxxxxx', 'x') code = code.replace('xxxx', 'x') code = code.replace('xx', 'x') code = code.replace('xx', 'x') code = code.replace('\nx', '\n') # Replacing x\n with \n would be incorrect because # x may be preceded by a backslash. # March over the squashed version of the program, accumulating # the line numbers of non-continued stmts, and determining # whether & why the last stmt is a continuation. continuation = C_NONE level = lno = 0 # level is nesting level; lno is line number self.goodlines = goodlines = [0] push_good = goodlines.append i, n = 0, len(code) while i < n: ch = code[i] i = i+1 # cases are checked in decreasing order of frequency if ch == 'x': continue if ch == '\n': lno = lno + 1 if level == 0: push_good(lno) # else we're in an unclosed bracket structure continue if ch == '(': level = level + 1 continue if ch == ')': if level: level = level - 1 # else the program is invalid, but we can't complain continue if ch == '"' or ch == "'": # consume the string quote = ch if code[i-1:i+2] == quote * 3: quote = quote * 3 firstlno = lno w = len(quote) - 1 i = i+w while i < n: ch = code[i] i = i+1 if ch == 'x': continue if code[i-1:i+w] == quote: i = i+w break if ch == '\n': lno = lno + 1 if w == 0: # unterminated single-quoted string if level == 0: push_good(lno) break continue if ch == '\\': assert i < n if code[i] == '\n': lno = lno + 1 i = i+1 continue # else comment char or paren inside string else: # didn't break out of the loop, so we're still # inside a string if (lno - 1) == firstlno: # before the previous \n in code, we were in the first # line of the string continuation = C_STRING_FIRST_LINE else: continuation = C_STRING_NEXT_LINES continue # with outer loop if ch == '#': # consume the comment i = code.find('\n', i) assert i >= 0 continue assert ch == '\\' assert i < n if code[i] == '\n': lno = lno + 1 if i+1 == n: continuation = C_BACKSLASH i = i+1 # The last stmt may be continued for all 3 reasons. # String continuation takes precedence over bracket # continuation, which beats backslash continuation. if (continuation != C_STRING_FIRST_LINE and continuation != C_STRING_NEXT_LINES and level > 0): continuation = C_BRACKET self.continuation = continuation # Push the final line number as a sentinel value, regardless of # whether it's continued. assert (continuation == C_NONE) == (goodlines[-1] == lno) if goodlines[-1] != lno: push_good(lno) def get_continuation_type(self): self._study1() return self.continuation def _study2(self): """ study1 was sufficient to determine the continuation status, but doing more requires looking at every character. study2 does this for the last interesting statement in the block. Creates: self.stmt_start, stmt_end slice indices of last interesting stmt self.stmt_bracketing the bracketing structure of the last interesting stmt; for example, for the statement "say(boo) or die", stmt_bracketing will be ((0, 0), (0, 1), (2, 0), (2, 1), (4, 0)). Strings and comments are treated as brackets, for the matter. self.lastch last interesting character before optional trailing comment self.lastopenbracketpos if continuation is C_BRACKET, index of last open bracket """ if self.study_level >= 2: return self._study1() self.study_level = 2 # Set p and q to slice indices of last interesting stmt. code, goodlines = self.code, self.goodlines i = len(goodlines) - 1 # Index of newest line. p = len(code) # End of goodlines[i] while i: assert p # Make p be the index of the stmt at line number goodlines[i]. # Move p back to the stmt at line number goodlines[i-1]. q = p for nothing in range(goodlines[i-1], goodlines[i]): # tricky: sets p to 0 if no preceding newline p = code.rfind('\n', 0, p-1) + 1 # The stmt code[p:q] isn't a continuation, but may be blank # or a non-indenting comment line. if _junkre(code, p): i = i-1 else: break if i == 0: # nothing but junk! assert p == 0 q = p self.stmt_start, self.stmt_end = p, q # Analyze this stmt, to find the last open bracket (if any) # and last interesting character (if any). lastch = "" stack = [] # stack of open bracket indices push_stack = stack.append bracketing = [(p, 0)] while p < q: # suck up all except ()[]{}'"#\\ m = _chew_ordinaryre(code, p, q) if m: # we skipped at least one boring char newp = m.end() # back up over totally boring whitespace i = newp - 1 # index of last boring char while i >= p and code[i] in " \t\n": i = i-1 if i >= p: lastch = code[i] p = newp if p >= q: break ch = code[p] if ch in "([{": push_stack(p) bracketing.append((p, len(stack))) lastch = ch p = p+1 continue if ch in ")]}": if stack: del stack[-1] lastch = ch p = p+1 bracketing.append((p, len(stack))) continue if ch == '"' or ch == "'": # consume string # Note that study1 did this with a Python loop, but # we use a regexp here; the reason is speed in both # cases; the string may be huge, but study1 pre-squashed # strings to a couple of characters per line. study1 # also needed to keep track of newlines, and we don't # have to. bracketing.append((p, len(stack)+1)) lastch = ch p = _match_stringre(code, p, q).end() bracketing.append((p, len(stack))) continue if ch == '#': # consume comment and trailing newline bracketing.append((p, len(stack)+1)) p = code.find('\n', p, q) + 1 assert p > 0 bracketing.append((p, len(stack))) continue assert ch == '\\' p = p+1 # beyond backslash assert p < q if code[p] != '\n': # the program is invalid, but can't complain lastch = ch + code[p] p = p+1 # beyond escaped char # end while p < q: self.lastch = lastch self.lastopenbracketpos = stack[-1] if stack else None self.stmt_bracketing = tuple(bracketing) def compute_bracket_indent(self): """Return number of spaces the next line should be indented. Line continuation must be C_BRACKET. """ self._study2() assert self.continuation == C_BRACKET j = self.lastopenbracketpos code = self.code n = len(code) origi = i = code.rfind('\n', 0, j) + 1 j = j+1 # one beyond open bracket # find first list item; set i to start of its line while j < n: m = _itemre(code, j) if m: j = m.end() - 1 # index of first interesting char extra = 0 break else: # this line is junk; advance to next line i = j = code.find('\n', j) + 1 else: # nothing interesting follows the bracket; # reproduce the bracket line's indentation + a level j = i = origi while code[j] in " \t": j = j+1 extra = self.indentwidth return len(code[i:j].expandtabs(self.tabwidth)) + extra def get_num_lines_in_stmt(self): """Return number of physical lines in last stmt. The statement doesn't have to be an interesting statement. This is intended to be called when continuation is C_BACKSLASH. """ self._study1() goodlines = self.goodlines return goodlines[-1] - goodlines[-2] def compute_backslash_indent(self): """Return number of spaces the next line should be indented. Line continuation must be C_BACKSLASH. Also assume that the new line is the first one following the initial line of the stmt. """ self._study2() assert self.continuation == C_BACKSLASH code = self.code i = self.stmt_start while code[i] in " \t": i = i+1 startpos = i # See whether the initial line starts an assignment stmt; i.e., # look for an = operator endpos = code.find('\n', startpos) + 1 found = level = 0 while i < endpos: ch = code[i] if ch in "([{": level = level + 1 i = i+1 elif ch in ")]}": if level: level = level - 1 i = i+1 elif ch == '"' or ch == "'": i = _match_stringre(code, i, endpos).end() elif ch == '#': # This line is unreachable because the # makes a comment of # everything after it. break elif level == 0 and ch == '=' and \ (i == 0 or code[i-1] not in "=<>!") and \ code[i+1] != '=': found = 1 break else: i = i+1 if found: # found a legit =, but it may be the last interesting # thing on the line i = i+1 # move beyond the = found = re.match(r"\s*\\", code[i:endpos]) is None if not found: # oh well ... settle for moving beyond the first chunk # of non-whitespace chars i = startpos while code[i] not in " \t\n": i = i+1 return len(code[self.stmt_start:i].expandtabs(\ self.tabwidth)) + 1 def get_base_indent_string(self): """Return the leading whitespace on the initial line of the last interesting stmt. """ self._study2() i, n = self.stmt_start, self.stmt_end j = i code = self.code while j < n and code[j] in " \t": j = j + 1 return code[i:j] def is_block_opener(self): "Return True if the last interesting statemtent opens a block." self._study2() return self.lastch == ':' def is_block_closer(self): "Return True if the last interesting statement closes a block." self._study2() return _closere(self.code, self.stmt_start) is not None def get_last_stmt_bracketing(self): """Return bracketing structure of the last interesting statement. The returned tuple is in the format defined in _study2(). """ self._study2() return self.stmt_bracketing if __name__ == '__main__': from unittest import main main('idlelib.idle_test.test_pyparse', verbosity=2)
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